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a^2+11a-350=0
a = 1; b = 11; c = -350;
Δ = b2-4ac
Δ = 112-4·1·(-350)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-39}{2*1}=\frac{-50}{2} =-25 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+39}{2*1}=\frac{28}{2} =14 $
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